How many solutions exist for the given equation?3x + 13 = 3(x + 6) + 1

Distribute the 3 on the right: 3(x + 6) + 1 = 3x + 19. The equation becomes 3x + 13 = 3x + 19, which would require 13 = 19 after subtracting 3x from both sides. Since that is impossible, there are zero solutions, choice A.

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