AnswersAZ-Algebra 1A MA101Solving Linear Equations: Variables on Both Sides

Solving Linear Equations: Variables on Both Sides Answers

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What is the solution to the linear equation?4b + 6 = 2 – b + 4

A
b = –2
B
b = 0
C
b = 4
D
b = 6
2
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Solve the equation.–3x + 1 + 10x = x + 4

A
x =
Option A
B
x =
Option B
C
x = 12
D
x = 18
3

Use properties to rewrite the given equation. Which equations have the same solution as the equation x + + x = – xSelect three options.x + = – x18x + 20 + 30x = 15 – 6x18x + 20 + x = 15 – 6x24x + 30x = –512x + 30x = –5

Question illustration
A
x + = – x
Option A
B
18x + 20 + 30x = 15 – 6x
C
18x + 20 + x = 15 – 6x
D
24x + 30x = –5
E
12x + 30x = –5
4

Two runners are saving money to attend a marathon. The first runner has $112 in savings, received a $45 gift from a friend, and will save $25 each month. The second runner has $50 in savings and will save $60 each month.

A
112 – 25m + 45 = 50 – 60m
B
112 + 25 + 45m = 50m + 60
C
112 + 25 – 45m = –50m + 60
D
112 + 25m + 45 = 50 + 60m
5

What is the solution to the linear equation?d – 10 – 2d + 7 = 8 + d – 10 – 3d

A
d = –5
B
d = –1
C
d = 1
D
d = 5
6

What is the solution to the linear equation?x – = + x

Question illustration
A
x = –5
B
x = –
Option B
C
x =
Option C
D
x = 5
7

Which number can each term of the equation be multiplied by to eliminate the fractions before solving?m – = 2 + m

Question illustration
A
2
B
3
C
4
D
5
8

Which number can each term of the equation be multiplied by to eliminate the fractions before solving?6 – x + = x + 5

Question illustration
A
2
B
3
C
6
D
12
9

Which number can each term of the equation be multiplied by to eliminate the decimals before solving?–m + 0.02 + 2.1m = –1.45 – 4.81m

A
0.01
B
0.1
C
10
D
100
10

The levels of mercury in two different bodies of water are rising. In one body of water the initial measure of mercury is 0.05 parts per billion (ppb) and is rising at a rate of 0.1 ppb each year. In the second body of water the initial measure is 0.12 ppb and the rate of increase is 0.06 ppb each year.

A
0.05 – 0.1y = 0.12 – 0.06y
B
0.05y + 0.1 = 0.12y + 0.06
C
0.05 + 0.1y = 0.12 + 0.06y
D
0.05y – 0.1 = 0.12y – 0.06

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