Question 84323 • FL-1200330-Algebra 2 CR
The quadratic is in standard form, y = ax² + bx + c, with a = 2, b = 0, and c = 3, so A is true. Substituting y = x + 6 from the second equation into the first gives 2x² + 3 = x + 6, or 2x² − x − 3 = 0, so B is true. This quadratic has discriminant (−1)² − 4(2)(−3) = 25, which is positive, so there are two real solutions and C is true. For x = −1, y = 5, not 1.5, so E is false.
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