AnswersIntegrated Math 2A - Mr. Katykhin 26Solving Linear-Quadratic Systems

Solving Linear-Quadratic Systems Answers

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1
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What are the solutions?

A
(–3, 4) and (0,1)
B
(–3, 4) and (–1,0)
C
(3, –4) and (1,0)
D
(–3, 4) and (1,0)
2
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What did you include in your response? Check all that apply.

A
Use substitution to create a one-variable equation.
B
Set the quadratic equation equal to zero and find the discriminant.
C
The value of the discriminant will tell you how many real number solutions the system of equations has.
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✔ –2024

A
✔ –2
B
0
C
2
D
4
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–4–2✔ –0.252

A
–4
B
–2
C
✔ –0.25
D
2
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–4–2–1✔ 2

A
–4
B
–2
C
–1
D
✔ 2
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David wants to find the solutions of this system of equations: –4x – 7 = yx2 – 2x – 6 = yWhich statement is true?

A
There are no real number solutions.
B
There is one unique real number solution at (–1, –3).
C
There is one unique real number solution at (1, –3).
D
There are two real number solutions at (–1, –3) and (1, –7).
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Explain how you can determine the number of real number solutions of a system of equations in which one equation is linear and the other is quadratic–without graphing the system of equations.

Answer:

Isolate one variable in the system of equations. Use substitution to create a onevariable equation. Then, set the quadratic equation equal to zero and find the discriminant. If the discriminant is negative, then there are no real number solutions. If the discriminant is zero, then there is one real number solution. If the discriminant is positive, then there are two real number solutions.

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