André solves the following system of equations by elimination. 3 A plus 6 b is equal to 12 negative 3 A plus 6 b is equal to negative 12 Which could be the resulting equations when André eliminates one of the variables?
Answer
A
negative 6 A is equal to 0
B
negative 12 b is equal to negative 24
C
6 A is equal to 0
D
12 b is equal to 0
Explanation
Add the equations term by term: (3A + 6b) + (−3A + 6b) = 12 + (−12). The A terms cancel, leaving 12b = 0, which is choice D, “12b is equal to 0.”
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