The solution to the given system of linear equations lies in which quadrant? x minus 3 y is equal to 6 x plus y is equal to 2

Subtract the second equation, x + y = 2, from the first, x − 3y = 6, to get −4y = 4, so y = −1. Substituting into x + y = 2 gives x = 3. Since x is positive and y is negative, the solution (3, −1) is in Quadrant IV.

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