AnswersLAUSD-Algebra II B Prescriptive - SummerUnit Test

Solving Logarithmic Equations using Technology Answers

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A teacher used the change of base formula to determine whether the equation below is correct.Which statement explains whether the equation is correct?

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A
The equation is correct since (log Subscript 2 Baseline 10) (log Subscript 4 Baseline 8) (log Subscript 10 Baseline 4) = log (2 times 10) times log (4 times 8) times log (10 times 4). = log (20) times log (32) times log (40). =3
Option A
B
The equation is correct since (log Subscript 2 Baseline 10) (log Subscript 4 Baseline 8) (log Subscript 10 Baseline 4) = StartFraction log 10 Over log 2 EndFraction times StartFraction log 8 Over log 4 EndFraction times StartFraction log 4 Over log 10 EndFraction. = StartFraction log 8 Over log 2 EndFraction. = 3
Option B
C
The equation is correct since (log Subscript 2 Baseline 10) (log Subscript 4 Baseline 8) (log Subscript 10 Baseline 4) = StartFraction log 10 Over log 2 EndFraction times StartFraction log 8 Over log 4 EndFraction times StartFraction log 4 Over log 10 EndFraction. = StartFraction log 8 Over log 2 EndFraction. = 4.
Option C
D
The equation is not correct since (log Subscript 2 Baseline 10) (log Subscript 4 Baseline 8) (log Subscript 10 Baseline 4) = log StartFraction 10 Over 2 EndFraction times log eight-fourths times log four-tenths. = log 5 times log 2 times log 0.4. = negative 0.08
Option D
2
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Kim solved the equation below by graphing a system of equations.What is the approximate solution to the equation?

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0
0.6
0
0.9
1
1.4
1
1.6
3

A student solved the equation below by graphing.Which statement about the graph is true?

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T
The curves do not intersect.
T
The curves intersect at one point.
T
The curves intersect at two points.
T
The curves appear to coincide.
4

Which is equivalent to ?

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Option
Option A
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Option
Option B
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Option
Option C
D
Option
Option D
5

Tyler applied the change of base formula to a logarithmic expression. The resulting expression is shown below. Which expression could be Tyler’s original expression?

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A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
6

Tenisha solved the equation below by graphing a system of equations.Which point approximates the solution for Tenisha’s system of equations?

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(
(0.9, 0.8)
(
(1.0, 1.4)
(
(2.3, 1.1)
(
(2.7, 13.3)
7

Which system of equations could be graphed to solve the equation below?

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A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
8

Devonte used the change of base formula to approximate . Which expression did Devonte use?

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A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
9

What is the approximate value of x in the equation below.

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A
–3.396
B
–0.708
C
0.304
D
0.955
10

Which system of equations could be graphed to solve the equation below?

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A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
11

What is the approximate value of q in the equation below?

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A
–1.613
B
–1.522
C
0.585
D
3.079
12

Which expression can be used to approximate the expression below, for all positive numbers a, b, and x, where a 1 and b 1?

Question illustration
A
StartFraction log Subscript b Baseline x Over log Subscript b Baseline a EndFraction
Option A
B
StartFraction log Subscript b Baseline a Over log Subscript b Baseline x EndFraction
Option B
C
StartFraction log Subscript a Baseline b Over log Subscript x Baseline b EndFraction
Option C
D
StartFraction log Subscript a Baseline x Over log Subscript b Baseline x EndFraction
Option D
13

Omar wants to use a graph to solve the equation below.Which system of equations should Omar use?

Question illustration
A
y 1 = StartFraction log 6 Over x EndFraction , y 2 = StartFraction log 2 Over x + 4 EndFraction
Option A
B
y 1 = StartFraction log x Over log 6 EndFraction, y 2 = StartFraction log x + 4 Over log 2 EndFraction
Option B
C
y 1 = StartFraction log 6 Over log 2 EndFraction, y 2 = StartFraction log x Over log (x + 4) EndFraction
Option C
D
y 1 = StartFraction log x Over log 6 EndFraction, y 2 = StartFraction log (x + 4) Over log 2 EndFraction
Option D

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