AnswersINMT3 Integrated Math 3 Sem 1 26-27Graphs of Polynomial Functions

Solving One-Variable Equations with Systems Answers

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Which graph can be used to find the solution(s) to x2 – 4x + 4 = 2x + 1 + x2?

A
Option
Option A
B
Option
Option B
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Option
Option C
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Option
Option D
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Tiffany is solving an equation where both sides are quadratic expressions. She sets each quadratic equation equal to y and graphs the resulting system. If the graph of one quadratic opens upward and the other opens downward, what is the greatest possible number of intersections for these graphs?

A
none
B
one
C
two
D
infinitely many
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What are the two solutions of 2x2 = –x2 – 5x – 1?

A
the y-coordinates of the intersection points of the graphs of y = 2x2 and y = –x2 – 5x – 1
B
the x-coordinates of the x-intercepts of the graphs of y = 2x2 and y = –x2 – 5x – 1
C
the x-coordinates of the intersection points of the graphs of y = 2x2 and y = –x2 – 5x – 1
D
the y-coordinates of the y-intercepts of the graphs of y = 2x2 and y = –x2 – 5x – 1
4

Carlos graphs the equations y = 0.5x2 + 3 and y = –4x2 + 24x – 35 and generates the graph below. Which conclusion is supported by the graph?

Question illustration
A
The equation 0.5x2 + 3 = –4x2 + 24x – 35 has no real solutions.
B
The equation 0.5x2 + 3 = –4x2 + 24x – 35 has one real solution.
C
The equation 0.5x2 + 3 = –4x2 + 24x – 35 has two real solutions.
D
The equation 0.5x2 + 3 = –4x2 + 24x – 35 has three real solutions.
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Which graph can be used to find the solution(s) to x2 – 1 = 3?

A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
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Vivek graphs the equations and to solve the equation . His graph is shown below. What are the solutions of ?

Question illustration
A
–4 and 2
B
–4 and 1
C
0 and 4
D
1 and 4
7

Trey graphs the equations y = –x2 + 2x + 3 and y = x2 – 2x + 3 to solve the equation –x2 + 2x + 3 = x2 – 2x + 3. His graph is shown below.What are the solution(s) of –x2 + 2x + 3 = x2 – 2x + 3?

Question illustration
A
–1 and 3
B
0 and 2
C
1
D
3
8

Fran graphs the equations and . Her graph is shown below. Which value is a solution of ?

Question illustration
A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
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Which graph can be used to find the solution(s) to x2 – 1 = x + 1?

A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
10

Heather is solving an equation by graphing the expressions on either side of the equal signs. If the graph intersects at an infinite number of points, which statement could describe the equation Heather is attempting to solve?

A
One side of the equation is a constant, and the other side of the equation is a linear expression.
B
One side of the equation is a linear expression, and the other side of the equation is a quadratic expression.
C
One side of the equation is a constant, and the other side of the equation is a quadratic expression.
D
One side of the equation is a quadratic expression, and the other side of the equation is a quadratic expression.
11

What is the solution of 3x + 5 = 2x – 7?

A
the x-coordinates of the intersection point of the lines y = 3x + 5 and y = 2x – 7
B
the x-coordinates of the x-intercepts of the lines y = 3x + 5 and y = 2x – 7
C
the y-coordinate of the intersection point of the lines y = 3x + 5 and y = 2x – 7
D
the y-coordinates of the y-intercepts of the lines y = 3x + 5 and y = 2x – 7
12

Sonia graphs the equations y = –x2 + 4x and y = x – 4 to solve the equation –x2 + 4x = x – 4. Her graph is shown below.What are the solutions of –x2 + 4x = x – 4?

Question illustration
A
–5 and 0
B
–5 and –1
C
–1 and 4
D
0 and 4
13

Michael graphs the equations and y = x + 1 to solve the equation . His graph is shown below. What are the solution(s) of ?

Question illustration
A
–1 and 8
B
1 and 4
C
2
D
3
14

Which system of equations can be graphed to find the solution(s) to ?

Question illustration
A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
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Which system of equations can be graphed to find the solution(s) to x2 = 2x + 3?

A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D

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