The real root of the equation x cubed minus 7 x squared plus 15 x minus 25 is equal to 0 is 5 What are the nonreal roots?

Since 5 is a root, divide the cubic by x − 5. The quotient is x² − 2x + 5, so the remaining roots satisfy x² − 2x + 5 = 0. Using the quadratic formula gives x = (2 ± √(4 − 20))/2 = 1 ± 2i, which matches 1 plus 2i and 1 minus 2i.

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