Answers FL-1200330-Algebra 2 CRSolving Polynomial Equations with Complex Solutions

Solving Polynomial Equations with Complex Solutions Answers

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Consider the equation 4x4 – 8x3 + 4x2 – 128x – 960 = 0. The real solutions are 5 and –3. What are the nonreal solutions?

–2i, 2i

–4i, 4i

–8i, 8i

–16i, 16i

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What are all the solutions to the equation 10x4 + 30x3 + 35x2 = 0?

0, StartFraction 3 + i StartRoot 5 EndRoot Over 2 EndFraction, StartFraction 3 minus i StartRoot 5 EndRoot Over 2 EndFraction.

0, StartFraction negative 3 + i StartRoot 5 EndRoot Over 2 EndFraction, StartFraction negative 3 minus i StartRoot 5 EndRoot Over 2 EndFraction.

0, 6 + 2 i StartRoot 5 EndRoot, 6 minus 2 i StartRoot 5 EndRoot.

0, negative 6 + 2 i StartRoot 5 EndRoot, negative 6 minus 2 i StartRoot 5 EndRoot.

If the real roots of the equation 3x4 – 6x3 + 3x2 – 54x – 216 = 0 are –2 and 4, what are the nonreal roots?

–3i, 3i

Negative 3 i StartRoot 3 EndRoot, 3 i StartRoot 3 EndRoot.

–9i, 9i

Negative 6 i StartRoot 6 EndRoot, 6 i StartRoot 6 EndRoot.

Consider the equation 3x3 + 14x2 – 14x + 60 = 0. The real solution is –6. What are the nonreal solutions?

Negative 2 i StartRoot 26 EndRoot, 2 i StartRoot 26 EndRoot.

4 minus 2 i StartRoot 26 EndRoot, 4 + 2 i StartRoot 26 EndRoot.

StartFraction negative 2 + i StartRoot 26 EndRoot Over 3 EndFraction, StartFraction negative 2 minus i StartRoot 26 EndRoot Over 3 EndFraction.

StartFraction 2 + i StartRoot 26 EndRoot Over 3 EndFraction, StartFraction 2 minus i StartRoot 26 EndRoot Over 3 EndFraction.

What are all the roots, both real and nonreal, of the equation x4 + x2 = 4x2 + 4?

Negative one-half, one-half, negative 2 i, 2 i.

Negative one-half, one-half, negative i, i.

Negative 1, 1, negative 2 i, 2 i.

Negative 2, 2, negative i, i.

Find all the solutions to 3x3 – 6x2 + 30x – 20 = –20.

0, 1 + 3i, 1 – 3i

0, 2 + 6i, 2 – 6i

0, –1 + 3i, –1 – 3i

0, –2 + 6i, –2 – 6i

On a coordinate plane, a curve goes through (negative 2, 0), has a minimum point at (negative 1, negative 40), increases through (0, negative 20), has an inflection point at (1.5, 0), and then increases.

Negative 2, 2, StartFraction negative 3 minus i Over 2 EndFraction, StartFraction negative 3 + i Over 2 EndFraction.

Negative 20, StartFraction 3 minus i Over 2 EndFraction, StartFraction 3 + i Over 2 EndFraction.

Negative 2, 2, StartFraction 3 minus i Over 2 EndFraction, StartFraction 3 + i Over 2 EndFraction.

Negative 20, StartFraction negative 3 minus i Over 2 EndFraction, StartFraction negative 3 + i Over 2 EndFraction.

Find all solutions to the equation x3 + 100x + 8x2 = –800.

–10, –8, 10

–10, 8, 10

8, –10i, 10i

–8, –10i, 10i

What are the solutions to –24x – 24 = x3 + 8x2?

Negative 1, negative 3 + i StartRoot 3 EndRoot, negative 3 minus i StartRoot 3 EndRoot.

1, 3 + i StartRoot 3 EndRoot, 3 minus i StartRoot 3 EndRoot.

2, 3 + i StartRoot 3 EndRoot, 3 minus i StartRoot 3 EndRoot.

Negative 2, negative 3 + i StartRoot 3 EndRoot, negative 3 minus i StartRoot 3 EndRoot.

Consider the equation 4x4 – 38x3 = 17x2 + 30x. One of the real solutions to the equation is 10. What are the other solutions, both real and nonreal?

0, StartFraction negative 1 + i StartRoot 11 EndRoot Over 4 EndFraction, StartFraction negative 1 minus i StartRoot 11 EndRoot Over 4 EndFraction.

1, StartFraction negative 1 + i StartRoot 11 EndRoot Over 4 EndFraction, StartFraction 1 minus i StartRoot 11 EndRoot Over 4 EndFraction.

1, StartFraction 1 + i StartRoot 11 EndRoot Over 4 EndFraction, StartFraction 1 minus i StartRoot 11 EndRoot Over 4 EndFraction.

0, StartFraction 1 + i StartRoot 11 EndRoot Over 4 EndFraction, StartFraction 1 minus i StartRoot 11 EndRoot Over 4 EndFraction.

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Solving Polynomial Equations with Complex Solutions Answers

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