Question 1 • Algebra I
Set the function equal to zero: 6x² + 12x − 7 = 0. Using the quadratic formula gives x = (−12 ± √(12² − 4·6·(−7)))/(2·6) = (−12 ± √312)/12 = −1 ± √(13/6). These are the zeros in choice B.
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