Which is a zero of the quadratic function f(x) = 16x2 + 32x − 9?

Set the function equal to zero: 16x² + 32x − 9 = 0. Using the quadratic formula gives x = (−32 ± √1600)/32 = (−32 ± 40)/32, so the roots are 0.25 and −2.25. Choice B, x = −2.25, is a zero of the function.

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