Question 7 • Algebra III A
Expand the left side: (x − 3)(x + 9) = x² + 6x − 27. Setting this equal to −27 gives x² + 6x = 0, or x(x + 6) = 0, so the solutions are x = 0 and x = −6. Among the choices, x = 0 is listed as choice C.
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