AnswersFL-1200710-Mathematics for College Algebra ASolving Quadratic Equations: Zero Product Property

Solving Quadratic Equations: Factoring Answers

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81697

Complete the equivalent equation for –7x – 60 = x2 + 10x.

Answers:
(x + )(x + ) = 0:5
(x + )(x + ) = 0:12
x =:–12 or –5
81698

–20–12✔ 1220

A
–20
B
–12
C
✔ 12
D
20
81699

–20 or 3✔ –12 or –5 –3 or 205 or 12

A
–20 or 3
B
✔ –12 or –5
C
–3 or 20
D
5 or 12
81752

⇒ 7

Answer:

81752

81754

Which statement is true about the equation (x – 4)(x + 2) = 16?

A
The equation x – 4 = 16 can be used to solve for a solution of the given equation.
B
The standard form of the equation is x2 – 2x – 8 = 0.
C
The factored form of the equation is (x + 4)(x – 6) = 0.
D
One solution of the equation is x = –6.
81755

What are the solutions of the equation 4x2 + 3x = 24 – x?

A
–3, 2, or 4
B
–3 or 2
C
–2, 3, or 4
D
–2 or 3
81759

Percy solved the equation x2 + 7x + 12 = 12. His work is shown below. Is Percy correct? Explain.1. (x + 3)(x + 4) = 12 2. x + 3 = 12 or x + 4 = 12 3. x = 9 or x = 8

Answer:

Percy is not correct because he tried to apply the zero product property to an equation that was not set equal to 0. He should have first subtracted 12 from both sides to get the equation in standard form, x^2 + 7x = 0. Then, he could factor it as x(x + 7) = 0. The correct solutions are x = 0 and x = -7.

81760

What did you include in your response? Check all that apply.

A
Percy was not correct.
B
Percy did not write the equation in standard form before factoring.
C
The correct solutions are 0 and –7.
D
The equation should have first been written as x2 + 7x = 0 before factoring.
E
The solutions 8 and 9 do not make the equation true.

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