Two children are throwing a baseball back and forth. The ball is 4 feet above the ground when it leaves one child’s hand with an upward velocity of 36 ft/s If acceleration due to gravity is negative 16 the fraction with numerator ft and denominator m squared , how high above the ground is the ball 2 s after it is thrown? h of t is equal to A t squared plus v t plus h sub 0
Use h(t) = At² + vt + h₀, where A is half the acceleration: −16 ÷ 2 = −8. After 2 seconds, h(2) = −8(2²) + 36(2) + 4 = −32 + 72 + 4 = 44 feet. None of the listed choices equals 44 feet, so the choices appear to contain an error.
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