Solve the quadratic equation numerically (using tables of x- and y- values).x(x + 5) = 0

To find where y = x(x + 5) equals 0, check values that make either factor zero. At x = 0, y = 0(5) = 0; at x = -5, y = (-5)(0) = 0. Thus the solutions are x = 0 and x = -5, matching choice b, “x = 0 or x = -5.”

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