Solve the quadratic equation numerically (using tables of x- and y- values).(x +2) (x + 3) = 12

Expand the left side: (x + 2)(x + 3) = x² + 5x + 6. Set it equal to 12 and subtract 12, giving x² + 5x − 6 = 0. This factors as (x + 6)(x − 1) = 0, so x = −6 or x = 1. The correct choice is “x = −6 or x = 1.”

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