Question 1 • FL-1200700-Mathematics for College Algebra MIS
Multiply the second equation, −2x + 6y = 14, by 3 to get −6x + 18y = 42. Add it to 6x − 3y = 3; the x-terms cancel, giving 15y = 45, so y = 3. Substitute y = 3 into the first equation: 6x − 9 = 3, so x = 2. The solution is (2, 3), choice D.
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