How many solutions does this linear system have?y = 2x – 5 –8x – 4y = –20

Substitute y = 2x − 5 into the second equation: −8x − 4(2x − 5) = −20. Simplifying gives −16x + 20 = −20, so x = 2.5; then y = 2(2.5) − 5 = 0. The system has exactly one solution, (2.5, 0), which is choice B.

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