AnswersAL-Algebra I with Probability Critical StandardsModeling with Two-Variable Linear Inequalities

Solving Systems of Linear Inequalities Answers

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Which ordered pairs make both inequalities true? Check all that apply.

A
(–2, 2)
B
(0, 0)
C
(1,1)
D
(1, 3)
E
(2, 2)
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y > 2x +2y > –2x – 1y < 2x + 2y < –2x – 1

A
y > 2x +2
B
y > –2x – 1
C
y < 2x + 2
D
y < –2x – 1
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Which system of inequalities with a solution point is represented by the graph?

A
y > 2x – 2 and y < x – 1; (3, 1)
B
y > 2x – 2 and y < x + 1; (–3, 1)
C
y > 2x + 2 and y < x – 1; (3, 1)
D
y > 2x + 2 and y < x + 1; (–3, 1)
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Which statements are true about the graph of y ≤ 3x + 1 and y ≥ –x + 2? Check all that apply.The slope of one boundary line is 2.Both boundary lines are solid.A solution to the system is (1, 3).Both inequalities are shaded below the boundary lines.The boundary lines intersect.

A
The slope of one boundary line is 2.
B
Both boundary lines are solid.
C
A solution to the system is (1, 3).
D
Both inequalities are shaded below the boundary lines.
E
The boundary lines intersect.
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Question text not available

Answer not available
76188

Graphically, a point is a solution to a system of two inequalities if and only if the point

A
lies in the shaded region of the top inequality, but not in the shaded region of the bottom inequality.
B
lies in the shaded region of the bottom inequality, but not in the shaded region of the top inequality.
C
lies in the shaded regions of both the top and bottom inequalities.
D
does not lie in the shaded region of the top or bottom inequalities.
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Which is the graph of the system x + 3y > –3 and y < One-half x + 1?

Question illustration
A
[Image: On a coordinate plane, 2 dashed lines are shown. T...]
B
[Image: On a coordinate plane, 2 dashed lines are shown. T...]
C
[Image: On a coordinate plane, 2 dashed lines are shown. T...]
D
[Image: On a coordinate plane, 2 dashed lines are shown. T...]
76191

Determine the relationship between the point (1, –5) and the given system of inequalities.y ≤ 3x + 2y > –2x – 3Explain your answer both algebraically and graphically.

Answer:

Algebraically, substituting (1, -5) into the inequalities yields -5 ≤ 3(1) + 2, which simplifies to -5 ≤ 5 (true), and -5 > -2(1) - 3, which simplifies to -5 > -5 (false). Graphically, the point (1, -5) lies within the shaded region of the first inequality's solid line but lies directly on the dashed boundary line of the second inequality. Because points on a dashed line are excluding, and the second inequality is not satisfied, (1, -5) is not a solution to the system.

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Sample Response: Algebraically, the point (1, -5) satisfies the first inequality, but it does not satisfy the second inequality because -5 is not greater than -5. Graphically, the point (1, -5) lies in the shaded area of the first inequality but lies on the dashed line of the second inequality, which is not inclusive. Therefore (1, -5) is not a solution to the given system of inequalities. What did you include in your response? Check all that apply.The point (1, –5) satisfies the first inequalit

A
The point (1, –5) satisfies the first inequality but not the second inequality.
B
The point (1, –5) lies in the shaded area of the first inequality, but not the second inequality.
C
The point (1, –5) lies on the dashed line of the second inequality, which is not inclusive.
D
The point (1, –5) is not in the solution set of the system of inequalities.

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