AnswersAPSB 2025 Math Essentials-ALPGraphing Two-Variable Linear Inequalities

Solving Systems of Linear Inequalities Answers

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1
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Which ordered pairs make both inequalities true? Check all that apply.

A
(–2, 2)
B
(0, 0)
C
(1,1)
D
(1, 3)
E
(2, 2)
2
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[___]

A
(–4, –2)
B
(–1, –2)
C
(1, 4)
D
(2, 2)
76184

[___]

A
y > 2x +2
B
y > –2x – 1
C
y < 2x + 2
D
y < –2x – 1
76185

(–4, –2)✔ (–1, –2)X (1, 4)(2, 2)

A
(–4, –2)
B
✔ (–1, –2)
C
X (1, 4)
D
(2, 2)
76186

Graphically, a point is a solution to a system of two inequalities if and only if the point

A
lies in the shaded region of the top inequality, but not in the shaded region of the bottom inequality.
B
lies in the shaded region of the bottom inequality, but not in the shaded region of the top inequality.
C
lies in the shaded regions of both the top and bottom inequalities.
D
does not lie in the shaded region of the top or bottom inequalities.
76188

Which system of inequalities with a solution point is represented by the graph?

A
y > 2x – 2 and y < x – 1; (3, 1)
B
y > 2x – 2 and y < x + 1; (–3, 1)
C
y > 2x + 2 and y < x – 1; (3, 1)
D
y > 2x + 2 and y < x + 1; (–3, 1)
76190

y > 2x +2y > –2x – 1y < 2x + 2y < –2x – 1

A
y > 2x +2
B
y > –2x – 1
C
y < 2x + 2
D
y < –2x – 1
76191

Which statements are true about the graph of y ≤ 3x + 1 and y ≥ –x + 2? Check all that apply.The slope of one boundary line is 2.Both boundary lines are solid.A solution to the system is (1, 3).Both inequalities are shaded below the boundary lines.The boundary lines intersect.

A
The slope of one boundary line is 2.
B
Both boundary lines are solid.
C
A solution to the system is (1, 3).
D
Both inequalities are shaded below the boundary lines.
E
The boundary lines intersect.
76193

Which ordered pairs make both inequalities true? Check all that apply.

A
(–2, 2)
B
(0, 0)
C
(1,1)
D
(1, 3)
E
(2, 2)
76194

Graphically, a point is a solution to a system of two inequalities if and only if the point

A
lies in the shaded region of the top inequality, but not in the shaded region of the bottom inequality.
B
lies in the shaded region of the bottom inequality, but not in the shaded region of the top inequality.
C
lies in the shaded regions of both the top and bottom inequalities.
D
does not lie in the shaded region of the top or bottom inequalities.
76196

Which is the graph of the system x + 3y > –3 and y < x + 1?

Question illustration
A
[Image: On a coordinate plane, 2 dashed lines are shown. T...]
Option A
B
[Image: On a coordinate plane, 2 dashed lines are shown. T...]
Option B
C
[Image: On a coordinate plane, 2 dashed lines are shown. T...]
Option C
D
[Image: On a coordinate plane, 2 dashed lines are shown. T...]
Option D
76197

Which system of inequalities with a solution point is represented by the graph?

A
y > 2x – 2 and y < x – 1; (3, 1)
B
y > 2x – 2 and y < x + 1; (–3, 1)
C
y > 2x + 2 and y < x – 1; (3, 1)
D
y > 2x + 2 and y < x + 1; (–3, 1)
76198

Which statements are true about the graph of y ≤ 3x + 1 and y ≥ –x + 2? Check all that apply.The slope of one boundary line is 2.Both boundary lines are solid.A solution to the system is (1, 3).Both inequalities are shaded below the boundary lines.The boundary lines intersect.

A
The slope of one boundary line is 2.
B
Both boundary lines are solid.
C
A solution to the system is (1, 3).
D
Both inequalities are shaded below the boundary lines.
E
The boundary lines intersect.
76199

How will the solution of the system y > 2x + and y 2x + ?

Question illustration
Answer:

The system of linear inequalities has no solution. Both equations have the same slope of -1, which means the boundary lines are parallel. Since the first inequality describes the region above the line $y = -x + 3$ and the second inequality describes the region below the line $y = -x - 2$, the shaded regions move in opposite directions and do not overlap. Because there are no points in common, the system has no solution.

76201

Determine the relationship between the point (1, –5) and the given system of inequalities.y ≤ 3x + 2y > –2x – 3Explain your answer both algebraically and graphically.

Answer:

Algebraically, substituting (1, -5) into the inequalities yields -5 ≤ 3(1) + 2, which simplifies to -5 ≤ 5 (true), and -5 > -2(1) - 3, which simplifies to -5 > -5 (false). Graphically, the point (1, -5) lies within the shaded region of the first inequality's solid line but lies directly on the dashed boundary line of the second inequality. Because points on a dashed line are excluding, and the second inequality is not satisfied, (1, -5) is not a solution to the system.

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