AnswersNC-Foundations of Math 1 Fall 1st 9 WeeksSolving with Variables on Both Sides

Solving with Variables on Both Sides Answers

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What could you do to isolate the variable term to one side of the equation?

A
Add 3x to both sides.
B
Subtract 3x from both sides.
C
Add 18 to both sides.
D
Subtract 18 from both sides.
3

x =

Answer:

1.8

5

Add 7/12 to both sides.Subtract 7/12 from both sides.Divide both sides by 7/12.Multiply both sides by 7/12.

A
Add 7/12 to both sides.
B
Subtract 7/12 from both sides.
C
Divide both sides by 7/12.
D
Multiply both sides by 7/12.
6

Question text not available

Answer:

Both students are correct. As long as inverse operations and the properties of equality are used properly, both methods will generate the same solution. They both serve to isolate the variable on one side of the equation, which is the objective when solving. It does not matter which term is moved first as long as the steps are performed correctly on both sides.

7

Sample Response: Both are correct. As long as inverse operations and the properties of equality are used properly, both methods will generate the same solution. They both isolate the variable on one side of the equation. Which did you include in your response?Both boys are correct.Both methods correctly use the properties of equality and inverse operations.Both methods isolate the variable to one side of the equals sign.

A
Both boys are correct.
B
Both methods correctly use the properties of equality and inverse operations.
C
Both methods isolate the variable to one side of the equals sign.
10

One-fifth x minus StartFraction 7 Over 3 EndFraction = negative one-half StartFraction 7 Over 10 EndFraction x = StartFraction 7 Over 3 EndFraction Negative StartFraction 7 Over 3 EndFraction = Negative StartFraction 7 Over 10 EndFraction x x = negative five-halves x + StartFraction 35 Over 3 EndFraction

A
Option
B
Option
C
Option
D
Option
E
Option
11

When Zack checked his solution, it didn’t work. What was his mistake?

A
In step 1, he should have used the multiplication property of equality.
B
In step 2, he should have a constant of – 4 on the right side.
C
In step 3, he should have divided both sides by .
D
In step 4, the answer should be positive.

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