AnswersNC-Foundations of Math 1 Fall 1st 9 WeeksSolving with Variables on Both Sides

Solving with Variables on Both Sides Answers

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1
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Which equation is equivalent to ?

Question illustration
A
Negative StartFraction 5 Over 6 EndFraction = one-fourth x + one-fourth
Option A
B
Two-thirds x = negative StartFraction 5 Over 12 EndFraction x minus StartFraction 7 Over 12 EndFraction
Option B
C
One-fourth x minus StartFraction 5 Over 6 EndFraction = one-fourth
Option C
D
Two-thirds x minus StartFraction 13 Over 12 EndFraction = negative StartFraction 5 Over 12 EndFraction x
Option D
2
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Tre determines the solution to the equation is . He verifies his solution using the steps below.Equation: Step 1: Step 2: Step 3: Which statement most accurately describes Tre’s error?

Question illustration
A
Tre made an error when determining the original solution of x = 0.5.
B
Tre made an error when substituting the solution in for x.
C
Tre made an error when multiplying each coefficient by 0.5.
D
Tre made an error when adding or subtracting.
3

What is the value of x in the equation ?

Question illustration
A
–22
B
–2
C
2
D
22
4

Carlton is solving a linear equation using the steps shown.Equation: Step 1: Add 4x to both sides: Step 2: Combine like terms: What is the next step he needs to complete in order to solve the equation?

Question illustration
A
Add –2 to both sides of the equation.
B
Subtract –2 from both sides of the equation.
C
Multiply each side of the equation by –2.
D
Divide each side of the equation by –2.
5

What is the value of x in the equation ?

Question illustration
A
–3
B
Negative one-third
Option B
C
One-third
Option C
D
3
6

What is the value of x in the equation ?

Question illustration
A
–7
B
–3
C
3
D
7
7

Which equations shows the variable terms isolated on one side and the constant terms isolated on the other side for the equation ? Select two options.

Question illustration
A
x = 5
B
–15 = –5x
C
5x = 15
D
–15 = 5x
E
x = -5
8

What is the solution to the equation ?

Question illustration
A
x = negative 5
Option A
B
x = negative 4
Option B
C
x = 4
Option C
D
x = 5
Option D
9

What is the solution to the equation ?

Question illustration
A
x = negative 3
Option A
B
x = negative 1
Option B
C
x = 1
Option C
D
x = 3
Option D
10

What is the solution to the equation ?

Question illustration
A
x = negative 2
Option A
B
x = negative one-half
Option B
C
x = one-half
Option C
D
x = 2
Option D
11

Louisa states that the solution to the equation is . She verifies her solution using the steps below. Equation: Step 1: Step 2: Step 3: Which statement most accurately describes Louisa’s error?

Question illustration
A
Louisa made an error when determining the original solution of x = 56.
B
Louisa made an error when substituting the solution in for x.
C
Louisa made an error when multiplying 56 by and by .
Option C
D
Louisa made an error when adding or subtracting.
12

What is the solution to the equation ?

Question illustration
A
One-third
Option A
B
Two-thirds
Option B
C
2
D
12
13

Horatio is solving the equation . Which equations represent possible ways to begin solving for x? Check all that apply.

Question illustration
A
Two-fifths x = StartFraction 7 Over 20 EndFraction x + one-fourth
Option A
B
Two-fifths x = StartFraction 7 Over 20 EndFraction x + five-fourths
Option B
C
Negative three-fourths = negative StartFraction 1 Over 20 EndFraction x minus one-half
Option C
D
Negative three-fourths = three-fourths x minus one-half
Option D
E
Negative three-fourths + StartFraction 1 Over 20 EndFraction x = negative one-half
Option E
14

What is the value of x in the equation ?

Question illustration
Answer not available
15

What is the value of x in the equation ?

Question illustration
A
–6
B
–2
C
2
D
6

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