The resting heart rates for 80 women aged 46 minus 55 in a simple random sample are normally distributed, with a mean of 71 beats per minute and a standard deviation of 6 beats per minute. Assuming a 90 percent confidence level open paren 90 percent confidence level is equal to z - score of 1 point 6 4 5 close paren , what is the margin of error for the population mean? Remember, the margin of error, ME , can be determined using the formula ME is equal to the fraction with numerator z times s and denominator square root of n
Use the margin-of-error formula ME = z × s / √n. Substituting the values gives ME = 1.645 × 6 / √80 ≈ 9.87 / 8.944 ≈ 1.10 beats per minute. Therefore, the correct choice is 1 point 1 0.
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