The chemical equation shows the reaction between carbon dioxide open paren CO sub 2 close paren and lithium hydroxide LiOH CO sub 2 plus 2 LiOH rightarrow Li sub 2 CO sub 3 plus cap h sub 2 cap o The molar mass open paren CO sub 2 close paren is 44 point 0 1 g over mol How many moles of LiOH are needed to react completely with 25 point 5 g of open paren CO sub 2 close paren ?
First convert carbon dioxide to moles: 25.5 g ÷ 44.01 g/mol ≈ 0.579 mol CO₂. The balanced equation shows that 2 moles of LiOH react with 1 mole of CO₂, so 0.579 × 2 ≈ 1.16 moles of LiOH are needed. The correct choice is 1.16 moles.
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