What is the mass of 9.45 mol of aluminum oxide (Al2O3)?
Answer
A
254 g
B
709 g
C
964 g
D
1120 g
Explanation
Aluminum oxide, Al₂O₃, has a molar mass of 2(26.98) + 3(16.00) = 101.96 g/mol. Multiply by 9.45 mol: 9.45 × 101.96 ≈ 964 g. The mass is 964 g, choice C.
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