Question 1 • *22SS - 1207350 - Mathematics for College Liberal Arts - Sem. 2 - CR
Each triangular face has a slant height of 13 inches: the pyramid’s 12-inch height and half the 10-inch base side form a right triangle, so √(12² + 5²) = 13. The four triangles have a combined area of ½ × 40 × 13 = 260 square inches, where 40 inches is the base perimeter. Add the 100-square-inch base to get 360 square inches, so the answer is D, 360 square inches.
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