If f of x is an odd function and the graph of f of x includes points in Quadrant IV, which statement about the graph of f of x must be true?

An odd function has origin symmetry: if (x, y) is on its graph, then (−x, −y) is also on the graph. A point in Quadrant IV has x > 0 and y < 0, so its reflected point has x < 0 and y > 0, placing it in Quadrant II. Therefore, the graph must include points in Quadrant II.

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