Question 2 • FL-1200330-Algebra 2 Sem 1 - Flex
For an odd function, every point (x, y) is paired with the point (−x, −y). So the six points in Quadrant I require six matching points in Quadrant III, using 12 of the 14 points. Any point in Quadrant II must be paired with a point in Quadrant IV, so the two remaining points can make at most one such pair. The greatest number in Quadrant II is one, choice A.
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