If a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then which statement would be true?

A rhombus has two lines of symmetry along its diagonals, and each diagonal bisects a pair of opposite angles. A square also has diagonal symmetry lines that bisect its angles, but it has four lines of symmetry, not exactly two. So the figure could be a rhombus, while the claims that it must be a rectangle or an isosceles trapezoid are not justified.

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