If f(x) is an odd function and the graph of f(x) includes points in Quadrant IV, which statement about the graph of f(x) must be true?

For an odd function, f(-x) = -f(x), so every point (x, y) on the graph is paired with (-x, -y). A point in Quadrant IV has x > 0 and y < 0; its paired point has x < 0 and y > 0, placing it in Quadrant II. Therefore, the graph must include points in Quadrant II.

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