Question 10 • FL-1200330-Algebra 2 Sem 1 - Flex
An odd function satisfies f(−x) = −f(x). In choice D, f(x) = 6x³ + 2x, so f(−x) = 6(−x)³ + 2(−x) = −6x³ − 2x = −f(x). Therefore, 6x³ + 2x is the odd function.
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