What is the solution to the system of equations? 2⁢x+4⁢y=12 y=(1)/(4)⁢x−3

Substitute y = x/4 − 3 into 2x + 4y = 12: 2x + 4(x/4 − 3) = 12. Simplifying gives 3x − 12 = 12, so x = 8; then y = 8/4 − 3 = −1. The solution is 8 comma negative 1, choice B.

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