A deli is offering two specials. The roast beef special gives a profit of 2 point 3 0 dollars per sandwich, and the turkey special gives a profit of 3 point 1 0 dollars per sandwich. The roast beef special uses two slices of bread and three slices of cheese. The turkey special uses two slices of bread and four slices of cheese. The deli has 120 slices of bread and 160 slices of cheese available for the specials. The deli wants to maximize its profit selling specials. Let x represent the number of roast beef specials and y represent the number of turkey specials. What are the constraints for the problem?
Answer
A
2 x plus 2 y is less than or equal to 120 3 x plus 4 y is less than or equal to 160 2 point 3 x is greater than or equal to 3 point 1 y
B
2 point 3 x plus 3 point 1 y is greater than or equal to 0 x is less than or equal to 120 y is less than or equal to 160
C
2 x plus 2 y is less than or equal to 120 3 x plus 4 y is less than or equal to 160 x is greater than or equal to 0 y is greater than or equal to 0
D
2 x plus 3 y is less than or equal to 120 2 x plus 4 y is less than or equal to 160 x is greater than or equal to 0 y is greater than or equal to 0
Explanation
Each roast beef or turkey special uses 2 slices of bread, so the bread constraint is 2x + 2y ≤ 120. Roast beef uses 3 slices of cheese and turkey uses 4, giving 3x + 4y ≤ 160. The numbers of specials cannot be negative, so x ≥ 0 and y ≥ 0. These are the constraints in choice D.
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