The constraints of a problem are listed. What are the vertices of the feasible region? x plus 3 y is less than or equal to 6 4 x plus 6 y is greater than or equal to 9 x is greater than or equal to 0 y is greater than or equal to 0

The feasible region is in the first quadrant, between the lines x + 3y = 6 and 4x + 6y = 9. On the y-axis, setting x = 0 gives y = 2 and y = 3/2, so the vertices there are (0, 2) and (0, 3/2). On the x-axis, setting y = 0 gives x = 6 and x = 9/4, so the other vertices are (6, 0) and (9/4, 0). These are the points listed in choice A.

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