What is the maximum value of cap p is equal to 24 x plus 30 y , given the constraints on x and y listed? x plus y is less than or equal to 5 x minus y is greater than or equal to negative 1 x is greater than or equal to 0 y is greater than or equal to 0

The maximum of this linear expression occurs at a corner of the feasible region. The relevant corners are (0, 0), (0, 1), (5, 0), and the intersection of x + y = 5 with y = x + 1, which is (2, 3). Evaluating 24x + 30y at those corners gives 0, 30, 120, and 138, respectively, so the maximum is 138, choice B.

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