Question 6 • Common Core Algebra II - MA3111 B-IC
The four seats are distinct, so who sits in each seat matters. There are 12 choices for the first seat, then 11, 10, and 9 choices for the remaining seats: 12 × 11 × 10 × 9 = 11,880. The correct choice is 11,880.
AI-written and checked against the verified answer.