What is the binomial expansion of (2x – 3)5?

Use the binomial theorem with coefficients 1, 5, 10, 10, 5, 1. Since the second term is −3, its powers alternate in sign: (2x)^5 − 15(2x)^4 + 90(2x)^3 − 270(2x)^2 + 405(2x) − 243. This matches choice A.

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