Question 10 • Precalculus
A parabola has a squared term for one variable but not the other. Choice C, −3x + 4y² − 2y + 6 = 0, has y² but no x²; rearranging gives x = (4/3)y² − (2/3)y + 2, which is a parabola. The other choices contain squared terms for both x and y.
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