AnswersPrecalculusThe General Equation of Conic Sections

The General Equation of Conic Sections Answers

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8

Which of the following equations would produce a parabola? Check all that apply.–5x2 + 4x – 7y + 14 = 0–x2 + 6x + y2 – 8 = 09x2 – 12xy + 4y2 + 4x – y + 5 = 012x + 6y – 5y2 + 14 = 020x2 + 10xy – y2 + 3x – 6y + 5 = 0

A
–5x2 + 4x – 7y + 14 = 0
B
–x2 + 6x + y2 – 8 = 0
C
9x2 – 12xy + 4y2 + 4x – y + 5 = 0
D
12x + 6y – 5y2 + 14 = 0
E
20x2 + 10xy – y2 + 3x – 6y + 5 = 0
13

What error, if any, did Jamaal make ?

A
Jamaal misidentified the center. The center should be at the point (–2, 3).
B
Jamaal did not complete the square correctly; he should have added 16 and 36 inside the parentheses in step 4. The radius is r = .
Option B
C
Jamaal added 4 and 9 to the right hand side in step 4; he should have added 16 and 36. The radius is r = 4.
D
Jamaal did not make an error.
14

Select the description of the graph created by the equation 3x2 – 6x + 4y – 9 = 0.

A
Parabola with a vertex at (1, 3) opening left.
B
Parabola with a vertex at (–1, –3) opening left.
C
Parabola with a vertex at (1, 3) opening downward.
D
Parabola with a vertex at (–1, –3) opening downward.
15

✔ ellipseparabolahyperbola

A
ellipse
B
parabola
C
hyperbola

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