What volume will 2.0 moles of nitrogen occupy at 720 torr and 20.0°C?Formula: PV = nRT (R = 62.396 L•torr/mol•K)

Convert the temperature to kelvins: 20.0°C + 273.15 = 293.15 K. Rearrange the ideal gas law to V = nRT/P, then substitute: V = (2.0 mol)(62.396 L·torr/mol·K)(293.15 K)/(720 torr) ≈ 50.8 L. Rounded to two significant figures, the volume is 51 L, choice D.

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