Question 11 • SVHS Chemistry 1 $FA
Use Einstein’s equation, E = mc², where the mass defect is 3.09 × 10⁻²⁷ kg and the speed of light is about 3.00 × 10⁸ m/s. Then E = (3.09 × 10⁻²⁷)(3.00 × 10⁸)² = 2.78 × 10⁻¹⁰ J. So the nuclear binding energy is 2.78 × 10⁻¹⁰ J.
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