Question 7 • IASD Precalculus 2nd Quarter - Wingerter 2025-26
For positive roots, read the signs of the coefficients of f(x): +, +, −, −, −. There is 1 sign change, so there is 1 possible positive real root. For negative roots, substitute −x to get f(−x) = x⁴ − 2x³ − 3x² + 8x − 4, whose signs are +, −, −, +, −. There are 3 sign changes, so the number of negative real roots can be 3 or 1. This matches choice A: positive 1; negative 3 or 1.
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