AnswersAZ-Common Core Algebra II AThe Rational Roots Theorem

The Rational Roots Theorem Answers

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3

–16–202

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9

0±2±4 ±9±3±6 ±12

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10

f(x) = 4x2 − 25 g(x) = 4x2 + 25 h(x) = 3x2 − 25

Answers:
Selection 1:Yes.
Selection 2:No, this polynomial has complex roots.
Selection 3:No, this polynomial has irrational roots.
12

–10 –7–531524

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13

Find all real solutions of this equation to answer the question.(6 – 2x)(3 – 2x)x = 40

A
Yes. Because [image 1] is a root, you can cut squares with sides of [image 2] in. to make the box
Option A
B
No. This equation has no real solutions.
C
No. The only real solution is x = 4. It is not possible to cut squares of this size.
14

Yuri thinks that [image 1] is a root of the following function.q(x) = 6x3 + 19x2 – 15x – 28Explain to Yuri why [image 2] cannot be a root.

Question illustration
Answer:

According to the rational root theorem, potential rational roots must be in theform where p is a factor of the constant term and q is a factor of the leading coefficient. 3 is not a factor of 28, and 4 is not a factor of 6. So, does not satisfy the rational root theorem. Substituting in for x does not result in 0. The remainder is not 0 when dividing by x –

15

Did you include the following in your response?

A
According to the rational root theorem, potential rational roots must be in theform where p is a factor of the constant term and q is a factor of the leading coefficient.
Option A
B
3 is not a factor of 28, and 4 is not a factor of 6. So, does not satisfy the rational root theorem.
Option B
C
Substituting [image 1] in for x does not result in 0. The remainder is not 0 when dividing by x – [image 2]
Option C
16

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20

✔ No, this polynomial has complex roots.No, this polynomial has irrational roots.No, this polynomial has irrational and complex roots.Yes.

A
No, this polynomial has complex roots.
B
No, this polynomial has irrational roots.
C
No, this polynomial has irrational and complex roots.
D
Yes.
28

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29

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The Rational Roots Theorem Answers — AZ-Common…