A padlock has a four-digit code that includes digits from 0 to 9, inclusive.What is the probability that the code does not consist of all odd digits if the same digit is not used more than once in the code?

There are 10 × 9 × 8 × 7 = 5,040 possible codes because digits cannot repeat. A code made entirely of odd digits uses 4 of the 5 odd digits, arranged in 5 × 4 × 3 × 2 = 120 ways. Therefore, 5,040 − 120 = 4,920 codes do not consist of all odd digits, so the probability is 4,920 out of 5,040, choice D.

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