Question 6 • CR - Algebra 2 26-27 - S2
Since zero is not allowed, the code’s digits come from 1 through 9. There are 9 × 8 × 7 = 504 possible codes when no digit is repeated. The available even digits are 2, 4, 6, and 8, so the number of three-digit codes using distinct even digits is 4 × 3 × 2 = 24. Thus the probability is 24 out of 504, choice A.
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