A substance has a specific heat of 0 point 8 7 0 the fraction with numerator cap j and denominator g times degree C It requires 2 comma 000 point 0 joules to increase the temperature of 10 point 0 grams of the substance from its original temperature to its final temperature. By how many degrees did the substance increase?
B
1 comma 740 times degree CC
87 point 0 times degree CUse the heat equation q = mcΔT, so ΔT = q/(mc). Substituting the values gives ΔT = 2,000.0 J ÷ (10.0 g × 0.870 J/(g·°C)) ≈ 230 °C. The temperature increased by 230 °C, which is choice A.
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