Miki has 104 nickels and 88 dimes. She wants to divide her coins into groups where each group has the same number of nickels and the same number of dimes. What is the largest number of groups she can have?

The number of groups must divide both 104 nickels and 88 dimes evenly. The greatest common divisor of 104 and 88 is 8: 104 = 8 × 13 and 88 = 8 × 11. So Miki can make at most 8 equal groups, with 13 nickels and 11 dimes in each group. The correct choice is 8.

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