If y varies directly as x and y = 208 when x = 16, what is the value of y when x = 11?

Direct variation means y = kx, where k is constant. Using y = 208 when x = 16 gives k = 208 ÷ 16 = 13, so when x = 11, y = 13 × 11 = 143. The correct choice is 143.

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