Randy draws triangle ABC on the coordinate plane with vertices A(7, –4), B(10, 3), and C(6, 1). He then translates the figure so the coordinates of the image are A′(5, 1), B′(8, 8), and C′(4, 6). What rule did he use to draw the image?
Triangle QRS has vertices Q(8, –6), R(10, 5), and S(–3, 3). What are the coordinates of the vertices of the image of the triangle after a translation of T–7.6, 4.3(x, y)? Q′ = R′ = S′ =
(–3.6, 9.3)✔ (2.4, 9.3) (14.6, –1.7) (16.4, 1.3)
(–3.4, –1.7) (–4.6, 7.3) (–9.4, –1.7)✔ (–10.6, 7.3)
Triangle ABC is translated to image A′B′C′. In this translation, A(5, 1) maps to A′(6, –2). The coordinates of B′ are(–1, 0). What are the coordinates of B?
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